SQL SERVER 2008 CTE生成結點的FullPath

SQL SERVER 2008 使用CTE是經常的事兒,有時我們想存儲一些冗余數據,像每個結點的FullPath。

好的,現在來看如何生成FullPath:
代碼如下:
DECLARE @tbl TABLE
(
Id int
,ParentId int
)
INSERT INTO @tbl
( Id, ParentId )
VALUES ( 0, NULL )
, ( 8, 0 )
, ( 12, 8 )
, ( 16, 12 )
, ( 17, 16 )
, ( 18, 17 )
, ( 19, 17 )

WITH abcd
AS (
— anchor
select id
,ParentID
,CAST(id AS VARCHAR(100)) AS [Path]
FROM @tbl
WHERE ParentId IS NULL
UNION ALL
–recursive member
SELECT t.id
,t.ParentID
,CAST(a.[Path] + ‘,’ + CAST( t.ID AS VARCHAR(100)) AS varchar(100)) AS [Path]
FROM @tbl AS t
JOIN abcd AS a ON t.ParentId = a.id
)
SELECT Id ,ParentID ,[Path]
FROM abcd
WHERE Id NOT IN ( SELECT ParentId
FROM @tbl
WHERE ParentId IS NOT NULL )

返回:
Id ParentID Path
———– ———– ———————-
18 17 0,8,12,16,17,18
19 17 0,8,12,16,17,19
就這么簡單,實際上有Sql server 2008中HierarchyType 也能很好的解決這個問題。我將在后面寫一些關于HierarchyType的Post.

希望這篇POST對您有幫助。

Author Peter Liu

? 版權聲明
THE END
喜歡就支持一下吧
點贊15 分享